5D Chess With Multiverse Time Travel – Some Opening Solution

Here is some solution of the game please avoid such opening since they’re totally solved.

Very Small – Open (Totally Solved)

All credit goes to 恨铁不成钢琴 !

First step for white, move rook to take black’s bishop.

1. Rxb4 ..

After take the bishop, there is no defense for d2, knight travel back to d2 make a checkmate.

Actually, black only have 3 valid moves here:

• a) Nb2
• b) Nc3
• c) Rxb4

Variation A):

1. .. Nb2
2. Bxb2 #

Variation B):

1. .. Nc3
2. Bxb2 ..

After that move, most of black’s pieces are blocked, no matter what black move, Bxc3+ then travel is a choice.

But sometimes there is no need to make such travel if c3 is not defended by black’s rook.

Variation Ba):

2. .. Rxb4
3. Bxc3 Kc4 (only move)
4. White would won if white does not move the bishop nor knight.

Variation Bb):

2. .. d2
3. Bxc3 Kd3 (only move)
4. Rxc4#

Variation C):

1. .. Rxb4
2. a3 ..

Variation c is the major variation, since it have many branches.

Firstly, if black don’t move rook, you could take the rook by your pawn and got a simple win.

Here, white could perform consecutive moves towards win, but only the strongest defense is shown.

Variation Ca):

2. .. Kc4
3. axb4=Q+ Kxb4
4. Nb2+ Nxb2
5. Bxb2#

The only choice is move rook here. but not move rook to b2 will fail easily, white could only move Bb2+ and then travel the Knight to d2 is enough to win.

Variation Cb):

2. .. R??
3. Bb2+ ??
4. Knight travels to (T2)d2 directly leads to a win.

Variation Cc):

2. .. Rb2+
3. Kxb2 Nc3+
4. Nxc3 ..
5. Nxc3 is crucial, without this action, black knight would travel to (T2)b3 and got a softmate. that softmate could not be solved.

White’s only legal move is travel Bishop to c4, but it failed to defend (-1LT3)b3.

After Nxc3, the strongest defense is

4. .. d1=Q
5. Nxd1 K??
6. a4=Q#

There might be some non-sense variations, but all of them could be defeated by a knight travel.

Small – Open (Partially Solved)

1. Rxd4

Firstly, black cannot take rook directly, since

1. .. Kxd4
2. Ne2+ K??
3. Ne2 travels to (T1)d2, which leads to a direct win.

Secondly, black cannot perform Rxb2, since Rd4 is really good at defending the b4 and d2 grid. thus white could perform Kxb2

There is a funny variation that make a check to prevent travelling to the two grids, in this case, you should notice you could perform Bxe4+

The branch is quite easy:

• Bxe4+ kxe4
• Ne2#

• Bxe4+ Bxe4
• Ne2+ then travel

It seems Rxd4 take lots of advantages here.

But I have not examine all the possibilities.